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Python Python Basics (2015) Shopping List App Break

Sreejith Unnikrishnan
Sreejith Unnikrishnan
2,407 Points
Posted by Sreejith Unnikrishnan
Sreejith Unnikrishnan
2,407 Points

The solution check seems not be working correctly. When i run the code in python interpreter, it seems to be working

Well the solution asks to iterate through the item list and then to break the loop when it finds "STOP". I believe the code does that, however the grader seems to say incorrect every time, any thoughts?

def loopy(items): ... # Code goes here ... for i in items: ... if i == "STOP": ... break ... else: ... print i ... loopy(["hello", 5, "STOP", "there"]) hello 5

breaks.py 
def loopy(items):
    # Code goes here
    for i in items:
      if i == "STOP":
        break
      else:
        print i

3 Answers

jcorum
jcorum
71,830 Points

So close!!

def loopy(items):
    # Code goes here
    for i in items:
      if i == "STOP":
        break
      else:
        print(i)

print is a function

jcorum
jcorum
71,830 Points
jcorum
jcorum
71,830 Points

Yes! Shades of Swift 1 vs Swift 2

Sreejith Unnikrishnan
Sreejith Unnikrishnan
2,407 Points
Sreejith Unnikrishnan
Sreejith Unnikrishnan
2,407 Points

Thank you so much!, Python 2 vs Python 3 in action :)