Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialjahnavi ette
838 Pointsthe code I entered looks correct but the when it is submitted it is not accepted
the code is not accepted as answer
// I have initialized a java.io.Console for you. It is in a variable named console.// I have initialized a java.io.Console for you. It is in a variable named console.
String inputFromUser;
String response;
do {
inputFromUser = console.readLine("Do you understand do while loops? ");
}
while(inputFromUser.equalsIgnoreCase("No"));
response = inputFromUser;
console.printf("Because you said " + response + ", you passed the test!");
1 Answer
jb30
44,806 PointsThe challenge is expecting console.printf
to be passed a formatted string, such as console.printf("%s", response)
, instead of using string concatenation.
Steven Parker
231,184 PointsSteven Parker
231,184 PointsYou also don't need the extra variable "inputFromUser". Everything can be done using just "response".