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Development Tools Database Foundations Creating Tables and Manipulating Data with SQL Creating a Table

Posted by Ted Sumner
Ted Sumner
Courses Plus Student 17,967 Points

Table created but returns an error.

I am using the following code to create a table. The table is created, but I get the following error: SQLSTATE[HY000]: General error: 1193 Unknown system variable 'cubScout'

<?php
require_once('pass.php');
$db_connection = '"mysql:host=localhost;dbname=' . DB_NAME . '","' . DB_USERNAME . '","' . DB_PASS . '"';

// call database
try {
    $db = new PDO("mysql:host=localhost;dbname=cubScout;charset=utf8mb4","root","");
    $db->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);

    $sql ='CREATE TABLE IF NOT EXISTS testing (
        id INT(11) NOT NULL AUTO_INCREMENT PRIMARY KEY,
        FirstName VARCHAR( 50 ) NOT NULL, 
        LastName VARCHAR( 50 ) NOT NULL,
        Den VARCHAR( 2 ) NOT NULL, 
        Bobcat VARCHAR( 150 ), 
        Tiger VARCHAR( 150 ), 
        Wolf VARCHAR( 100 ),
        Bear VARCHAR( 100 ),
        Webelo VARCHAR( 100 ),
        Arrow VARCHAR( 100 ),
        Health VARCHAR( 500 ),
        CampMoney DECIMAL(5,2))';
    $db->exec($sql);
    $db->exec("SET cubScout 'utf8mb4'");
    echo "Created Table.\n";
} catch (Exception $e) {
    echo $e->getMessage();
    exit;
}

The code above the try is not relevant to the error. It is not used in the try and does not return an error on its own.

Thank you in advance.

1 Answer

Ted Sumner
Ted Sumner
Courses Plus Student 17,967 Points

The error was from the 

<?php
$db->exec("SET cubScouts 'utf8mb4'");

When I change cubScouts to NAMES, the error goes away.