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iOS Functions in Swift Adding Power to Functions Function Parameters

Swift Functions

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, a and b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

Does this not look correct? What am I missing or doing wrong?

functions.swift
// Enter your code below
func getRemainderWith(Value a: Int, Divisor b: Int) -> Int {
  let remainder = a % b
return remainder

}

2 Answers

You are using Value and Divisor with an uppercase letter.

Swift is picky about capitalization, so change them to value and divisor.

I fixed it but nothing happened.

Hey Keifer,

Like Alexander stated, you need to keep your external variable names consistent with the Challenge's directions. On the same note, you'll want to fix the name of your function so that it matches the function-name the Challenge told you to use.