Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialAdrian Storr
2,660 Pointsstuck on wood, I need some assistance with this ....
// Display the prompt dialogue while the value assigned to `secret` is not equal to "sesame"
let secret = prompt("What is the secret password?");
// This should run after the loop is done executing
alert("You know the secret password. Welcome!");
let secret;
do {
secret = prompt("What is the secret password");
} while( secret !== "sesame");
document.write("you know the secret password");
2 Answers
Michael Kobela
Full Stack JavaScript Techdegree Graduate 19,570 PointsThe variable secret has been defined in two places. Remove the line
let secret;
after the alert and it should work. The keyword let will not allow you to redefine a variable.
David Mclean
3,646 PointsAs Michael explained you have declared secret twice. The only time you can do this is if your declaring a new variable with the same name in a function.