Stuck again

Hey, I'll do my best to explain this to you as I think you posted about this before. If you have any questions ask them and if I can't help I know someone who can!

Here's your solution so far.

available = "banana split;hot fudge;cherry;malted;black and white"
sundaes=available.split(";")
menu="Our favourite flavours are:()".format          # <-- ()

Here's my solution to the challenge, I'm gonna go through it step by step.

available = "banana split;hot fudge;cherry;malted;black and white"

sundaes = available.split(';')

menu = "Our available flavors are: {}"

menu = menu.format(", ".join(sundaes))

Firstly, the bit I commented on in your code, the brackets on that line are the wrong type of brackets in this scenario, we use the curly braces , {}, when formatting with strings.

When it comes to using .format(), you need to have the braces within the string at the position you want to slot in whatever it may be, in this case the sundaes all joined together, so lets join the sundaes.

', '.join(sundaes)

When using .join() you choose how you want to join whatever you are joining first, so we want a comma and a space so that is the first part of the statement, then in the brackets we choose the subject of the statement, which is the variable sundaes.

Using .format() is what I'll focus on now. With .format() you want a string (the .join() makes us a string from a list) to be able to use it. So we join the sundaes together, this could have been done in a variable but I prefer doing it in the .format() as it saves a bit of typing.

.format() looks for the curly braces within the string and then replaces them with whatever is in the brackets on .format(), so in this case that is the joined version of sundaes.

Then I save the formatted version of the menu under the same name, menu, to update it.