Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

pedroquellemen
pedroquellemen
125 Points
Posted by pedroquellemen
pedroquellemen
125 Points

Strings

I have this problem and i try 3 times please somebody can help

JavaTester.java:74: error: ')' expected Console console = ("s% is studyng java" , "firstName"); ^ JavaTester.java:74: error: expected Console console = ("s% is studyng java" , "firstName"); ^ JavaTester.java:74: error: illegal start of expression Console console = ("s% is studyng java" , "firstName"); ^ 3 errors

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "peter";
Console console = ("s% is studyng java" , "firstName");

3 Answers

Aayush Mitra
Aayush Mitra
24,904 Points

Hi!

First of all you do not need to create an instance of the Console object, he has already done that for you.

Next, It is %s, not s%.

Finally, you do not need to put quotes around the variable. Change: "firstName" to firstName.

Here is the code for this challenge:

// I have setup a java.io.Console object for you named console
String firstName = "Peter";
console.printf("%s can code in Java!", firstName);

I hope this helps!

Thanks! :)

jacobproffer
jacobproffer
24,604 Points
jacobproffer
jacobproffer
24,604 Points

Hey Pedro,

You're close. For the second challenge, you'll want to use the printf function. Remove the assignment and call the printf function on console. Note that you'll want to use %s and not s%. You also need to pass a variable and not a string as an argument.

Here is an example:

String example = "Jacob";
console.printf("%s is my name!", example);
pedroquellemen
pedroquellemen
125 Points
pedroquellemen
pedroquellemen
125 Points

Thank you guys I appreciatte!!