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Java

Posted by Ted Clayton
Ted Clayton
Courses Plus Student 206 Points

String equality objectives

Challenge Task 1 of 2 Add an if statement that checks to see if firstExample is equal to secondExample. If it is, print out "first is equal to second". ? My coding is below and it wouldn't run. However, once I took secondExample out of quotes it did run. Will someone explain why that is?

if (firstExample.equals("secondExample")) { console.printf("first is equal to second. \n\n");

2 Answers

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! It's because secondExample is a variable name. Now that variable likely holds a string. But let's say firstExample holds the string "Treehouse". Let's also say that secondExample holds "Treehouse". When you put secondExample in quotes, you are giving a string literal. It will ask then if "Treehouse" is equal to "secondExample" (the string). What you want to know is if the value in firstExample and the value in secondExample are the same.

Hope this helps! :sparkles:

Ted Clayton
PLUS
Ted Clayton
Courses Plus Student 206 Points
Ted Clayton
Ted Clayton
Courses Plus Student 206 Points

Jennifer, Thank you for the reply.