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Start your free trialFrederik Munk-Petersen
714 PointsString Equal
Cant find my problem...
// I have imported a java.io.Console for you, it is named console.
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {
console.printf("first is equal to second");
if (firstExample.equalsIgnoreCase(thirdExample)) {
console.printf("first and third are the same ignoring case");
}
2 Answers
Jennifer Nordell
Treehouse TeacherHi there, Frederik Munk-Petersen ! You're doing terrific and you're literally off by one single character. Your very first if
statement starts off strong and contains a console.printf statement, but then it isn't closed by a curly closing brace }
. There should be a closing curly brace at the end of the first if
statement.
Hope this helps!
Frederik Munk-Petersen
714 PointsThank you so much. I finally got it :D
Frederik Munk-Petersen
714 PointsFrederik Munk-Petersen
714 PointsLike this ?
becourse that did not work :(
Jennifer Nordell
Treehouse TeacherJennifer Nordell
Treehouse TeacherFrederik Munk-Petersen you were meant to do that without altering the following
if
statement.Your second
if
statement started like this:if (firstExample.equalsIgnoreCase(thirdExample))
That was correct. But now it starts with:
if (firstExample equalsIgnoreCase thirdExample)
And this will give you compiler errors. You were meant to simply insert a closing curly brace after the first
console.printf()
statement and before the followingif
statement.