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Python Python Basics (2015) Number Game App Squared

Posted by Sirui Ma
Sirui Ma
1,371 Points

Squared function cannot return correct values for "2"

Hi, I wrote the code as below, but i cannot get correct values. If you enter 5, it can give you 25, but if you enter "5", it will only give you "5""5""5". Anyone know the reason? Thanks!

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(letter):
    try:
        num=int(letter)
    except ValueError:
        letter*len(letter)
    else:
        int(letter)*int(letter)

1 Answer

Henrik Christensen
seal-mask
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points
Henrik Christensen
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points

You are told to return the value in the except block and the value in the else block.

# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(x):
    try:
        num = int(x)
    except ValueError:
        return x * len(x)  # notice the return
    else:
        # here I don't understand why you are doing (just a tip):
        # int(letter) * int(letter) when you already have int(letter) stored in the num variable
        return num * num  # notice the return