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5,113 PointsSorting characters into 2 lists problem
Does this problem call anything from Example.java? I know it needs to be looking at the character's first index and then sorting it into line 1 or 2, so it needs the scanner object, right?
import java.util.Scanner;
public class ConferenceRegistrationAssistant {
if ('C' < 'D') {
System.out.println("C comes before D");
}
if ('B' > 'A') {
System.out.println("B comes after A");
}
if ('E' >= 'E') {
System.out.println("E is equal to or comes after E");
}
/**
* Assists in guiding people to the proper line based on their last name.
*
* @param lastName The person's last name
* @return The line number based on the first letter of lastName
*/
public int getLineNumberFor(String lastName) {
int lineNumber = 0;
Scanner scan = new Scanner(System.in);
String name = scan.nextLine();
lineNumber = assistant.getLineNumberFor(name)
/*
lineNumber should be set based on the first character of the person's last name
Line 1 - A thru M
Line 2 - N thru Z
*/
return lineNumber;
}
}
public class Example {
public static void main(String[] args) {
/*
IMPORTANT: You can compare characters using <, >. <=, >= and == just like numbers
*/
if ('C' < 'D') {
System.out.println("C comes before D");
}
if ('B' > 'A') {
System.out.println("B comes after A");
}
if ('E' >= 'E') {
System.out.println("E is equal to or comes after E");
}
// This code is here for demonstration purposes only...
ConferenceRegistrationAssistant assistant = new ConferenceRegistrationAssistant();
/*
Remember that there are 2 lines.
Line #1 is for A-M
Line #2 is for N-Z
*/
int lineNumber = 0;
/*
This should set lineNumber to 2 because
The last name is Zimmerman which starts with a Z.
Therefore it is between N-Z
*/
lineNumber = assistant.getLineNumberFor("Zimmerman");
/*
This method call should set lineNumber to 1, because 'A' from "Anderson" is between A-M.
*/
lineNumber = assistant.getLineNumberFor("Anderson");
/*
Likewise Charlie Brown's 'B' is between 'A' and 'M', so lineNumber should be set to 1
*/
lineNumber = assistant.getLineNumberFor("Brown");
}
}
1 Answer
Johan Cederschiöld
5,708 PointsHi, You will not need the scanner object. Try using the charAt() method on the last name string to get the first letter in the last name. This char can be used to determine which line should be used (I.e. If char n < 'M' sort into line 1. I hope this helps.