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Start your free trialEdwin Amaya
Courses Plus Student 809 Pointssorry, im stumped .. seems simple enough i must be missing something so obvious its ridiculous
keeps telling me the output does not show the dispenser..the code is baby simple..what am i doing wrong??? its too early ZZzz help please.
public class Example {
public static void main(String[] args) {
ShoppingCart cart = new ShoppingCart();
Product pez = new Product("Cherry PEZ refill (12 pieces)");
cart.addItem(pez, 5);
/* Since a quantity of 1 is such a common argument when adding a product to the cart,
* your fellow developers have asked you to make the following code work, as well as keeping
* the ability to add a product and a quantity.
*/
Product dispenser = new Product("Yoda PEZ dispenser");
cart.addItem(dispenser);
}
}
public class ShoppingCart {
public void addItem(Product item, int quantity) {
System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
/* Other code omitted for clarity */
}
public void addItem(Product thing)
{
System.out.printf("Adding 1 %s to the cart.%n",thing.getName());
}
}
public class Product {
/* Other code omitted for clarity, but you could imagine
it would store price, options like size and color
*/
private String mName;
public Product(String name) {
mName = name;
}
public String getName() {
return mName;
}
}
1 Answer
Marileen Mennerich
1,161 PointsIn your new addItem-method (the one that only takes a Product), you are not supposed to write an output yourself. Instead, you should call the pre-existing addItem-method with your Product and a quantity of 1.
Edwin Amaya
Courses Plus Student 809 PointsEdwin Amaya
Courses Plus Student 809 Pointsahhhh, the whole "dont repeat your self " i forgot that ...seems silly though since we never ask the user to enter a quantity we are hardwiring it in the code