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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Yusuf Gillani
.a{fill-rule:evenodd;}techdegree
Yusuf Gillani
Python Web Development Techdegree Student 3,643 Points

Sorry guys. I can't get my head around this.

Help Please :(

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while True:
    random.randint(1,99)

1 Answer

mhjp
mhjp
20,372 Points

You are on the right track, your while loop should use the start var that was declared above instead of just True.

Then assign your random.randint to a variable.

Check if its even or odd.

Print if its even or odd. i.e. Print("{} is odd".format()).

Decrement start by 1.