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Java Java Objects (Retired) Harnessing the Power of Objects Handling Exceptions

Gabriel Llanes
Gabriel Llanes
2,894 Points
Posted by Gabriel Llanes
Gabriel Llanes
2,894 Points

Someone please help, stuck on the lesson!! No error just an unclear "bummer!" hint

The bummer says, please print out to the console using a System.out object....

I believe that is exactly what I am doing am I missing something????

Main.java 
public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
      try {
      kart.drive(-3);
      System.out.println("This will never happen");
      } catch(IllegalArgumentException iae){
        System.out.println("Woah there!");
        System.out.printf("The error was: %s \n", iae.getMessage());
      }
      }
}

1 Answer

jcorum
jcorum
71,830 Points

You have:

      try {
      kart.drive(-3);
      System.out.println("This will never happen");
      } catch(IllegalArgumentException iae){
        System.out.println("Woah there!");
        System.out.printf("The error was: %s \n", iae.getMessage());
      }

I deleted two of your System.out.println() statements, and put 2 back as the argument to drive():

      try {
        kart.drive(2);
      } catch(IllegalArgumentException iae) {
        System.out.printf("The error was: %s \n", iae.getMessage());
      }

and it worked.