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C# C# Streams and Data Processing Serialization Serializing to a File

Christer Monsen
Christer Monsen
3,664 Points

[SOLVED] Code Challenge 4 of 4 Serializer

using System; using System.IO; using System.Collections.Generic; using Newtonsoft.Json;

namespace Treehouse.CodeChallenges { public class Program { public static void Main(string[] arg) { } public static void SerializeWeatherForecasts(List<WeatherForecast>weatherForecasts, string fileName) {

        var serializer = new JsonSerializer();
        using (var writer = new StreamWriter(fileName))
        using (var jsonWriter = new JsonTextWriter(writer))
        {
            serializer.Serialize(jsonWriter, weatherForecasts);
        }
   }

   public static WeatherForecast ParseWeatherForecast(string[] values)
   {
        var weatherForecast = new WeatherForecast();
        weatherForecast.WeatherStationId = values[0];
        DateTime timeOfDay;
        if (DateTime.TryParse(values[1], out timeOfDay))
        {
            weatherForecast.TimeOfDay = timeOfDay;
        }
        Condition condition;
        if (Enum.TryParse(values[2], out condition))
        {
            weatherForecast.Condition = condition;
        }
        int temperature;
        if (int.TryParse(values[3], out temperature))
        {
            weatherForecast.Temperature = temperature;
        }
        double precipitation;
        if (double.TryParse(values[4], out precipitation))
        {
            weatherForecast.PrecipitationChance = precipitation;
        }
        if (double.TryParse(values[5], out precipitation))
        {
            weatherForecast.PrecipitationAmount = precipitation;
        }
        return weatherForecast;
    }

    public static List<WeatherForecast> DeserializeWeather(string fileName)
    {
        var weatherForecasts = new List<WeatherForecast>();

        using (var reader = new StreamReader(fileName))
        using (var jsonReader = new JsonTextReader(reader))
        {
            var serializer = new JsonSerializer();
            weatherForecasts = serializer.Deserialize<List<WeatherForecast>>(jsonReader);
        }

        return weatherForecasts;
    }
}

}

Christer Monsen
Christer Monsen
3,664 Points

Edited: a second parameter for Serialize but it still tells me "Bummer! The second parameter in the 'Serialize' should be 'weatherForecasts'."

2 Answers

Steven Parker
Steven Parker
231,198 Points

:point_right: Your call to serializer.Serialize is missing the second argument.

It looks like you're actually on task 4, not task 2. The instructions for task 4 are: "Inside the using block, call the Serialize method from the serializer object. The Serialize method takes a JsonTextWriter as its first parameter, and a List<WeatherForecast> as its second parameter."

Your call to serializer.Serialize has only one argument. Add the second one and you'll have it.

I'm still lost on no.4 I've got public static void SerializeWeatherForecasts(List<WeatherForecast> weatherForecasts,string fileName){ var serializer = new JsonSerializer (); using (var writer = new StreamWriter(fileName)) using (var JsonTextWriter = new JsonTextWriter(writer)) { serializer.Serialize (JsontWriter, List<WeatherForecast> ); }

                } 

But still not working