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Start your free trialCJ Doyle
1,530 PointsSo I did this problem on Xcode before putting in the system in treehouse and it worked. Why not here?
for i in 1..100 { if (i % 3 == 0) && (i % 5 == 0) { print("FizzBuzz") } else if (i % 3 == 0) { print("Fizz") } else if (i % 5 == 0) { print("Buzz") } else { print(i) } }
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for i in 1..100 {
if (i % 3 == 0) && (i % 5 == 0) {
print("FizzBuzz")
} else if (i % 3 == 0) {
print("Fizz")
} else if (i % 5 == 0) {
print("Buzz")
} else {
print(i)
}
}
// End code
return "\(n)"
}
4 Answers
KRIS NIKOLAISEN
54,971 PointsThere are a few things in the instructions that weren't followed.
1) Change your variable/constant name that you are checking in each step to n
2) Change all your print statements to return statements
3) Do not worry about the default case
4) The challenge also does not need you to loop over a range of values
CJ Doyle
1,530 PointsYeah before I copied I had changed over the variables to n, changed the statements to return and didn't do a default case and it still didn't work..didnt realize I still had the one before.
KRIS NIKOLAISEN
54,971 PointsSo it works now? Here is your code updated that passed for me:
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (n % 3 == 0) && (n % 5 == 0) {
return("FizzBuzz")
} else if (n % 3 == 0) {
return("Fizz")
} else if (n % 5 == 0) {
return("Buzz")
}
// End code
return "\(n)"
}
CJ Doyle
1,530 PointsI ended up doing a switch statement instead one more time and it passed actually. But thank you so much for the help with the if statement... I See where I where I went wrong this time.