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Start your free trialChristian Trolle
508 PointsSkipping item in list if the index 0 in a word is =='a'
The question is "Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz"."
I have two issue.
- how do is identify the index 0 in a word ? so far is have said item[so] =='a'
- how do I skip the item if the if-statement is fulfilled? I have used: if items[0] =='a': next(item)
I hope someone can help me out :)
def loopy(items):
# Code goes here
for item in items
if items[0] =='a':
next(item)
print(item)
3 Answers
Abdishakur Hassan
3,585 PointsHi. You are almost there. You have all the necessary bits of code. Instead of next (item). Just write continue. your code should look like this.
def loopy(items):
# Code goes here
for item in items:
if item[0] == 'a':
continue
print(item)
```
Christian Trolle
508 PointsThank you Abdishakur!!
valerakushnir
2,265 PointsI don't quite grasp what's happening in here:
if items [0] == 'a':
continue
Can someone explain in plain English? :)