Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialNina Kozlova
11,602 Pointssearch_challenges
Why did it not find the right number of challenges?
Here is my code:
def search_challenges(name, language): return Challenge.select().where(Challenge.name == name, Challenge.language == language)
Thank you
from models import Challenge
def create_challenge(name, language, steps=1):
Challenge.create(name=name,
language=language,
steps=steps)
def search_challenges(name, language):
return Challenge.select().where(Challenge.name == name, Challenge.language == language)
3 Answers
hebendjd
7,626 PointsChallenge.name should be checked to see if it contains name, unlike Challenge.language wich should be checked for equality .
Steven Parker
231,269 PointsI don't understand the challenge's statement "You don't need boolean and ...". So how else are you to "just put both conditions in your where()
"?
Anyway, if you ignore the confusing advice and replace your comma with and, it passes the challenge.
def search_challenges(name, language):
return Challenge.select().where(Challenge.name == name and Challenge.language == language)
paul amato
2,707 PointsI had same experience, did not work but added the "and" and challenged passed.