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Start your free trialBin Chen
627 PointsScrambler challenge question
I am not sure how to go back this code next and was wondering if someone could help here.
public class ScrabblePlayer {
// A String representing all of the tiles that this player has
private String tiles;
public ScrabblePlayer() {
tiles = "";
}
public String getTiles() {
return tiles;
}
public void addTile(char tile) {
tiles += tile;
}
public boolean hasTile(char tile) {
return tiles.indexOf(tile) != -1;
}
public int getCountOfLetter(char letter) {
int count = 0;
if (tile == letter) {
count = count++;
}
}
//return count;
}
// This code is here for example purposes only
public class Example {
public static void main(String[] args) {
ScrabblePlayer player1 = new ScrabblePlayer();
player1.addTile('d');
player1.addTile('d');
player1.addTile('p');
player1.addTile('e');
player1.addTile('l');
player1.addTile('u');
ScrabblePlayer player2 = new ScrabblePlayer();
player2.addTile('z');
player2.addTile('z');
player2.addTile('y');
player2.addTile('f');
player2.addTile('u');
player2.addTile('z');
int count = 0;
// This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
count = player1.getCountOfLetter('p');
// This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
count = player1.getCountOfLetter('d');
// This would set 0, because there isn't an 'a' tile in player1's tiles
count = player1.getCountOfLetter('a');
// This will return 3 because player2 has 3 'z' tiles in his collection of tiles
count = player2.getCountOfLetter('z');
// This will return 1 because player2 has 1 'f' tiles in his collection of tiles
count = player2.getCountOfLetter('f');
}
}
1 Answer
Dmitry Zhdakhin
2,480 PointsPlease check getCountOfLetter() function. Note "tiles" is a String property declared in ScrabblePlayer class so it's accessible in all functions. "letter" is a char parameter of getCountOfLetter() function so it's accessible in this function only. Using "tile" in getCountOfLetter() function is wrong because getCountOfLetter() doesn't have this parameter. We should use "for" loop to iterate through "tiles" string and compare each letter with "letter" parameter: for(char nexttile : tiles.toCharArray()) { if (nexttile == letter) { ... code to count letters ...} }