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JavaScript JavaScript Array Iteration Methods Array Manipulation Practice map()

Says " The correct result is stored in `abbreviatedDays` but `map` was not used."

What Am I doing wrong here

app.js
const daysOfWeek = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
let abbreviatedDays;

// abbreviatedDays should be: ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"]
// Write your code below

const days = daysOfWeek.map(day => day.substr(0,3));

abbreviatedDays = days;

3 Answers

Greg Kaleka
Greg Kaleka
39,021 Points

Hi Victor,

Your code definitely works. I think you’re just confusing the challenge by setting a constant days. Instead, just set the value of abbreviatedDays directly (remove const days).

Cheers ?

Greg

The questions says: Use the map method on the daysOfWeek array, creating a new array of abbreviated week days. Each abbreviated string should be the first three letters of the long version in daysOfWeek. Store the new array in the variable abbreviatedDays.

what would another way be to solve it. I tried

const daysOfWeek = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
let abbreviatedDays = daysOfWeek.map(day => day.substr(0,3));

and it says:

Bummer! It looks like you changed or removed the provided code. You can hit "Restart" if you want to start over.

Got it right:

const daysOfWeek = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
let abbreviatedDays;

// abbreviatedDays should be: ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"]
// Write your code below

abbreviatedDays = daysOfWeek.map(days => days.substr(0,3));
Greg Kaleka
Greg Kaleka
39,021 Points

Yep - this is what I was suggesting. Glad you figured it out!