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Elijah Florence
Courses Plus Student 3,225 PointsSays I am not passing parameter
Says I am not passing firstName parameter to printf function?
// I have imported java.io.Console for you. It is a variable called console.
String firstName = "Elijah";
console.readLine("Elijah");
String lastName;
lastName = console.readLine("Florence");
console.printf("First name: %s", firstName);
1 Answer
Jeremy Hill
29,567 PointsYou are supposed to set the String variable to the user's name using console.readLine(); You do that for their first and last name. then you add a printf line repeating their first name and then their last name. Like this:
String firstName = console.readLine("What is your first name?%n");
String lastName = console.readLine("What is your last name?%n");
console.printf("First name: %s", firstName);
console.printf("Last name: %s", lastName);
Jeremy Hill
29,567 PointsJeremy Hill
29,567 PointsWhen you do console.readLine it is a prompt that allows a user to enter in information being asked by the program, after the user enters in the information it is then stored into the variable that you set it equal to. After that you just do a printf statement that tells them what their first and last name is using the '%s' as variable place holders for the variable that you add after the comma.