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Python Python Basics (2015) Shopping List App Continue

Sun Min
Sun Min
2,941 Points
Posted by Sun Min
Sun Min
2,941 Points

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items a

am i doing wrong? i can not figure out this challenge!! :(

breaks.py 
 def loopy(items):
    for item in items:
        if item.index[0] == 'a':
            continue
        else:
            print(items)

1 Answer

andren
andren
28,558 Points
andren
andren
28,558 Points

There are two main issues:

Firstly you have typed "print(items)" instead of "print(item)" in your else statement.

Secondly you are using the index method incorrectly, the index method takes the thing you are looking for as an argument and then returns it's index. You are passing in the index and then comparing what it returns to the character 'a' which is incorrect.

But that is also a somewhat moot point, because the index method is actually not very well suited for this kind of task in the first place. The index method will raise an exception if the character you ask it to find is not present, which is not what you want in a situation like this.

The better way of checking if 'a' is at index 0 is to use bracket syntax like this: item[0] == 'a' , that will retrieve the character at index 0 of the item string and compare it to 'a'.

Sun Min
Sun Min
2,941 Points
Sun Min
Sun Min
2,941 Points

Thank you!