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Start your free trialKarthikeyan s
Courses Plus Student 2,444 Pointsruby looping
please help me to solve this
def repeat(string, times)
counter = 0
if times <= counter
loop do
break
end
else
puts string
counter += 1
end
end
fail = "times must be 1 or more"
repeat(fail, 2)
#def repeat(string, times)
#counter = 0
# loop do
# if times == counter
# loop do
# break
# end
# else
# puts string
# counter += 1
# end
# end
#end
#fail = "times must be 1 or more"
#repeat(fail, 3)
1 Answer
Ari Misha
19,323 PointsHiya Karthikeyan! The challenge wants ya to print "string" variable and increment the counter everytime you print the "string" that "repeat" function is recievin'. And when your counter reaches the "times" variable, the loop should break out. Here is the code for your reference:
def repeat(string, times)
fail "times must be 1 or more" if times < 1
counter = 0
loop do
# YOUR CODE HERE
puts "#{string}"
counter += 1
if counter == times
break
end
end
end
Karthikeyan s
Courses Plus Student 2,444 PointsKarthikeyan s
Courses Plus Student 2,444 PointsThanks, Ari Misha.