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Start your free trialFrank Greek
Full Stack JavaScript Techdegree Student 981 PointsReturn
function counter() {
for (let count = 1; ; count++) { // infinite loop
console.log(`${count}A`); // until 5
if (count === 5) {
return;
}
console.log(`${count}B`); // until 4
}
console.log(`${count}C`); // never appears
}
counter();
// Logs:
// 1A
// 1B
// 2A
// 2B
// 3A
// 3B
// 4A
// 4B
// 5A
Why this code runs for B only until 4 and never appear for C
1 Answer
Mark Sebeck
Treehouse Moderator 37,799 PointsHi Frank. Because of your if statement. You have the If after you print A. So when count === 5 it will first print 5A then the if statement will be true and it will return. Return exits the function and returns control back to the calling program. Since you have no more program it ends. If you change to a break statement you would break out of the for statement and print 5C after 5A then return.
Hope this helps Frank. Good luck