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Start your free trialRamona marian
1,126 PointsReplace the hard coded values in the output with the name and email values from the contacts array.
My code doesn;t work
<?php
//edit this array
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
$contacts = [
["name" => "Alena Holligan",
"email" => "alena.holligan@teamtreehouse.com"],
["name" => "Dave McFarland",
"email" => "dave.mcfarland@teamtreehouse.com"],
["name" => "Treasure Porth",
"email" => "treasure.porth@teamtreehouse.com"],
["name" => "Andrew Chalkley",
"email" => "andrew.chalkley@teamtreehouse.com"]
];
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li> Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";
echo "<li>Dave McFarland : dave.mcfarland@teamtreehouse.com</li>\n";
echo "<li>Treasure Porth : treasure.porth@teamtreehouse.com</li>\n";
echo "<li>Andrew Chalkley : andrew.chalkley@teamtreehouse.com</li>\n";
echo "</ul>\n";
echo "<ul>\";
echo "<li>" . $contacts[0]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[1]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[2]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[3]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
1 Answer
Steven Parker
231,268 PointsThe challenge wants you to "Replace the hard coded values in the output..." (not echo them a second time).
Also, the index values for the email must match the ones for the name on each line (instead of all being 0).