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Start your free trialFilipe Couto
Full Stack JavaScript Techdegree Student 2,521 Pointsreplace firstName variable using the string formatter.
cant see whats wrong with my code
// I have setup a java.io.Console object for you named console
String firstName ="Filipe";
console.printf ("%s can code in Java",firstname);
1 Answer
Jason Anders
Treehouse Moderator 145,860 PointsHey there Filipe,
You misspelled the firstName
variable in the printf()
statement. The original variable has an upper-cased 'N.'
Keep Coding!
Filipe Couto
Full Stack JavaScript Techdegree Student 2,521 PointsFilipe Couto
Full Stack JavaScript Techdegree Student 2,521 Pointstks for the reply ,
i try both 'n' and 'N'
String firstName ="Filipe"; console.printf ("%s can code in Java",firstname);
or String firstName ="Filipe"; console.printf ("%s can code in Java",firstName);