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Start your free trialCesar Garcia
Full Stack JavaScript Techdegree Student 5,184 PointsReduce Method Question
Hey all - I'm not sure what I'm doing wrong here. Every time I run the code, it adds up to 6 instead of 3. What am I missing?
const phoneNumbers = ["(503) 123-4567", "(646) 123-4567", "(503) 987-6543", "(503) 234-5678", "(212) 123-4567", "(416) 123-4567"];
let numberOf503;
// numberOf503 should be: 3
// Write your code below
numberOf503 = phoneNumbers.reduce( (count, number) => {
for ( let i = 0; i < phoneNumbers.length; i++ ) {
if ( number[i][1] === '5') {
return count + 1;
}
return count;
}
}, 0);
1 Answer
Chris Adams
553 PointsYou're extremely close to the solution here, Cesar Garcia! It's worth taking a deeper look at how the reduce()
method operates. By now you're probably pretty familiar with the forEach()
method - it iterates over every element in an array. You define a function to be executed on each of these elements as they're iterated over.
reduce()
works in a very similar way. This method iterates over every element in an array automatically, but gives us a bit of additional flexibility and functionality in the form of a counter variable. It's really just a value that gets passed to the next iteration, and to the next, and to the next, etc.
So we're looking at a syntax that reads like this:
yourArray.reduce( (previousValue, currentValue) => { /* ..... */ }, initialValue);
Or in your current implementation:
phoneNumbers.reduce( (count, number) => { /* ..... */ }, 0);
count
is the value carried through each iteration (and is eventually returned by the function).
number
is the current value or current index being evaluated within the array.
0
is the initial value that we'll start our count at.
So let's take a look at what you're trying to do inside the function:
for ( let i = 0; i < phoneNumbers.length; i++ ) {
if ( number[i][1] === '5') {
return count + 1;
}
return count;
}
Instead of immediately performing your test on the current number in the phoneNumber
array, you're introducing an unnecessary additional nested for loop
. This means that every index in the initial phoneNumber array runs its own loop*. Hence why your final count is larger than expected.
const phoneNumbers = ["(503) 123-4567", "(646) 123-4567", "(503) 987-6543", "(503) 234-5678", "(212) 123-4567", "(416) 123-4567"];
let numberOf503;
// numberOf503 should be: 3
// Write your code below
numberOf503 = phoneNumbers.reduce( (count, number) => {
if ( number[1] === '5') {
return count + 1;
}
return count;
}
}, 0);
If we remove the additional nested loop, you should return the correct result. However, just keep in mind that this solution would tally all numbers starting with a 5, and not just numbers starting with "503" as the instructions suggest.
I'd love to see if you can solve the challenge using an additional method on the String object! https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String