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Start your free trialChristian Geib
826 PointsReceive error message, seems indentation issue
So this is what I have used:
def loopy(items): # Code goes here for item in items: print(item) if item == 'STOP': break I am quite sure it is an indentation issue but even if I indent the if item loop a bit further I still receive the Bummer error message
def loopy(items):
# Code goes here
for item in items:
print(item)
if item == 'STOP':
break
2 Answers
Greg Kaleka
39,021 PointsHi Christian,
You've got two issues with your code. 1. is indentation, which you correctly identified. Note that your indentation is wrong in just the right way - it would still pass the challenge because you've just indented one block of code a bit too much. That said, we should still fix it. It should look like this:
def loopy(items):
# Code goes here
for item in items: # no need to indent this further. Still just inside loopy block
print(item)
if item == 'STOP':
break
The second issue is the order of your code. It's not 100% clear from the challenge prompt, but my interpretation - and the code that passes the challenge - is that if the item is "STOP" you should not print that item, but instead break out of the loop immediately. To do this we just need to flip the order of your if..STOP..break and the print statement:
def loopy(items):
# Code goes here
for item in items:
if item == 'STOP':
break
print(item)
Hopefully that clears things up!
Cheers
-Greg
Thomas McDonnell
8,212 PointsHi Christian Geib, You just have some code a little jumbled up. lets word it out!
for item in items: ........if item == "STOP": .................break .........print(item)
I always find playing with my code in the python shell helps needle out some of these kinds of issues.
Hope this helps:)
Christian Geib
826 PointsThanks, Thomas, that is extremely helpful! Thank you very much:-)!
Christian Geib
826 PointsChristian Geib
826 PointsThanks, Greg for your comprehensive and illuminating response. Extremely helpful, it did the trick! Cheers:-)