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Start your free trialkristoffer tølbøll
1,337 Pointsquestion regarding ! and integers
Can someone explain this
public static void main(String[] args){ int i = 7; int j = 12; if(!(i == 7 || j == 7)){ System.out.println("Fire"); } else { System.out.println("Water"); } } }
why is the outcome Water and not fire?
1 Answer
Damien Watson
27,419 PointsHey, the ! symbol means 'not', so if it is !(int i == 7) then it means if 'i' is not equal to 7, which it is, so it fails and shows water.
public static void main(String[] args){
int i = 7;
int j = 12;
// if not (i==7 OR j==7) but i does == 7, so show Water
if(!(i == 7 || j == 7)){
System.out.println("Fire");
} else {
System.out.println("Water");
}
}