Question about an exercise that asks me to create an odd_even function

Question

The question asks me to create a function called odd_even that takes one parameter that is a number, and check if that number is even or odd.  If even return True, if odd, return False.  I created the following function which works fine in Visual Studios Python IDE. But I got "Bummer" when I checked my work  Perhaps Treehouse wanted me to use the keyword return instead of print.  But they didn't specify that as a requirement as far as I can tell.   
def even_odd(num):
     if(num%2 ==0):
         print("True")
     else:
         print("False")
```even.py
```

Jeremy Hill · Answer

There are a couple things preventing you from getting it right:
One is you shouldn't be using parenthesis in your if statements in Python.
Number two: Your logic looks good, however the assignment tells you to "return" the result, not print the result.
You were real close though :)
In case you still don't understand here is my code:
```python
def even_odd(num):
    if num % 2 == 0:
        return True
    else:
        return False
```

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rodian

rodian

Question about an exercise that asks me to create an odd_even function

1 Answer

Jeremy Hill

Jeremy Hill