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Start your free trialAlbert Reel
5,555 PointsPython refactoring cant catch 'HELP' str.
My work starts @#22
I can't find where the break is to all the 'HELP' string to be received. How do I run a test to see where the failure is?
def show_help():
# print out instructions on how to use the app
print("What should we pick up at the store?")
print("""
Enter 'DONE' to stop adding items.
Enter 'HELP' for this help.
Enter 'SHOW' to see your current list.
""")
def show_list(shopping_list):
# print out the list
print("Here's your list:")
for item in shopping_list:
print(item)
def add_to_list(shopping_list, new_item):
# add new items to our list
shopping_list.append(new_item)
print("Added {}. List now has {} items.".format(new_item, len(shopping_list)))
return shopping_list
def main():
# make a list to hold onto our items
shopping_list = []
while True:
new_item = input("> ")
if new_item == 'DONE':
show_list(shopping_list)
break
elif new_item == 'HELP':
show_help()
continue
elif new_item == 'SHOW':
show_list(shopping_list)
continue
add_to_list(shopping_list, new_item)
2 Answers
Albert Reel
5,555 PointsThe function failed the test because an initial call to the function show_help() inserted as seen below. This brings up the instructions when the function is called but before input is taken.
def main():
show_help() #This line is the solution
shopping_list = []
while True:
new_item = input("> ")
Albert Reel
5,555 PointsCannot find anything wrong with the program. It functions as intended and should be working but is not.
Albert Reel
5,555 PointsAlbert Reel
5,555 PointsI found A testing solution:
Added to the bottom of the code allows main() to be called. This allows you to debug the code once it has been refactored into a function.