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Kong Cheong
633 PointsPython basics: number-game-app/even-or-odd. I am a little stuck on how to write this one.
Write a function named even_odd that takes a single argument, a number. return True if the number is even, or False if the number is odd. You can use % 2 to find out the remainder when dividing a number by 2. Even numbers won't have a remainder....
4 Answers
Kevin Faust
15,353 Pointsfirst create the function. a number will be passed in as an argument:
def even_odd(number):
check if its even using the % sign. if we divide the number by 2 and we get 0, then it is even. return true if this is the case.
def even_odd(number):
if number % 2 == 0 :
return True
else:
return False
or a short form
def even_odd(number):
return number % 2 == 0
which directly returns whether or not the remainder after the division is 0
Kong Cheong
633 PointsCool! Thanks Kevin. I was testing around and I was very close while trying to get help. thanks again!
Kevin Faust
15,353 Pointsglad ya understand now
Jonathan Newsome
2,773 PointsI know this is a year old, but here is what I tried and it worked fine:
def even_odd(number): if not number % 2 : return True else: return False
Bryan Castillo
2,484 Pointsthe % part confused me big time. anyone care to explain?
Marc Dantin
965 Points% is different from "/" which indicates division. What % returns is the remainder of a division. 12 / 3 = 4 12 % 3 = 0
or
5 % 3 = 2 (5 divided by 3 gives you 1 with a remainder of 2, the "%" only returns that "2")