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Python Python Basics (2015) Logic in Python Membership

Posted by Ahmed Naeem
Ahmed Naeem
353 Points

Python Basics "In" challenge task 1-1

"I'm going to create a variable named time. It'll be an integer for the current hour (well, what I want the current hour to be). I need you to make an if condition that sets store_open to True if time is in store_hours. If time isn't in store_hours, set store_open to False. You'll probably have to use if, else, and in to solve this one."

store_open = 10
store_hours = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
if store_open in store_hours:
  print("True")
else:
  print("False")

It's a Bummer! ..sometimes the error message says False and True. Can somebody please help. Thanks. Cheers!

3 Answers

Tobias Mahnert
Tobias Mahnert
89,414 Points
Tobias Mahnert
Tobias Mahnert
89,414 Points

Hello Ahmed,

you're very close. Did you see in the question that there is a time variable that you have to check in the hours? Check the code Below and have a look. 

if time in store_hours:
  store_open = True
else:
  store_open = False
Ahmed Naeem
Ahmed Naeem
353 Points

Thank you very much. It worked.

Ary de Oliveira
Ary de Oliveira
28,298 Points
Ary de Oliveira
Ary de Oliveira
28,298 Points

Challenge Task 1 of 1

I'm going to create a variable named time. It'll be an integer for the current hour (well, what I want the current hour to be). I need you to make an if condition that sets store_open to True if time is in store_hours. If time isn't in store_hours, set store_open to False. You'll probably have to use if, else, and in to solve this one.

if time in store_hours:

 store_open = True

else:

  store_open = False
Sonny Lee
Sonny Lee
7,883 Points
Sonny Lee
Sonny Lee
7,883 Points

If I define "time" variable first, the entire code will error out. Bummer.

time = 14 if time in store_hours: <snap>

Ahmed Naeem
Ahmed Naeem
353 Points

Yeah I was doing the same mistake. Actually time variable is pre-defined.