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Start your free trialEric Roberts
291 PointsPublic Class Question
Hi Guys,
When I type this code: public class Example {
public static void main(String[] args) {
// Your amazing code goes here...
System.out.println("We are making a new Pez Dispenser.");
PezDispenser dispenser = new PezDispenser();
System.out.printf("The Dispenser character is %s\n",
dispenser.mCharacterName);
}
}
I get this error: Example.Java:8: error: cannot find symbol dispenser.mCharacterName); symbol: Variable mCharacterName variable dispenser of type PezDispenser 1 error
Here is the code I've written for PezDispenser.java:
public class PezDispenser { public String characterName = "Yoda"; }
Ive gone through the video many times and cannot see where my error is. Any help would be appreciated. Thanks.
2 Answers
Geovanie Alvarez
21,500 PointsWell the problem is the name of the variable, in the class class PezDispenser you call the variable characterName and then in the System.out.printf you call the variable mCharacterName.
typetypetypetype
Courses Plus Student 1,033 PointsI'll jump in - I had an issue with this also and you have to compare item to item.
For example in PezDispenser.java I named the variable mcharacterName but then in example.java I named it mCharacterName because that's what the instructor had.
Kinda sloppy for a teacher, at 5:31 you'll see the change from characterName (inside the dispenser java) to mCharacterName (as in Example.java).
It's a good lesson to learn, but the video doesn't call it the capital case change out, so you really have to look for it. 30 minutes later.... :)