Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialNoelle Acheson
610 PointsProgram works in preview, but I get an error message saying it doesn't work
Hello, in "Preview" I get 2 System.out statements, one about the 5 Pez dispenser order, and one with the 1 Pez dispenser order. But when I "check" the work, I get an error message that says that the program doesn't recognize my 1 Pez dispenser order. But the compiler does, so I'm confused. What am I doing wrong?
public class Example {
public static void main(String[] args) {
ShoppingCart cart = new ShoppingCart();
Product pez = new Product("Cherry PEZ refill (12 pieces)");
cart.addItem(pez, 5);
/* Since a quantity of 1 is such a common argument when adding a product to the cart,
* your fellow developers have asked you to make the following code work, as well as keeping
* the ability to add a product and a quantity.
*/
Product dispenser = new Product("Yoda PEZ dispenser");
/* Uncomment the line following this comment,
after adding a new method using method signatures,
to solve their request in ShoppingCart.java
*/
cart.addItem(dispenser);
}
}
public class ShoppingCart {
public void addItem(Product item, int quantity) {
System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
/* Other code omitted for clarity. Please imagine
lots and lots of code here. Don't repeat it.
*/
}
public void addItem(Product item) {
System.out.printf("Adding 1 %s to the cart.%n", item.getName());
}
}
public class Product {
/* Other code omitted for clarity, but you could imagine
it would store price, options like size and color
*/
private String mName;
public Product(String name) {
mName = name;
}
public String getName() {
return mName;
}
}
2 Answers
Logan R
22,989 PointsYou're on the right track. Instead of implementing the same method twice, just call the method and pass in the argument of 1.
public void addItem(Product item) {
addItem(item, 1);
}
Kristian Terziev
28,449 PointsImagine you had a different program where such message is used in 20 methods. Now what happens when you need to change that message? It's quite easy to miss some places and that may cause undesired issues. Therefore we must not repeat ourselves (hence DRY). So in the new method you create, it's better the call the old method where the message is already written. That way you can change the message on only one place if needed be. Meaning:
public void addItem(Product item) {
addItem(item, 1);
}
Craig Dennis
Treehouse TeacherGreat response Kristian Terziev !