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Python Python Basics (2015) Letter Game App Even or Odd Loop

aditya yadav
aditya yadav
1,505 Points
Posted by aditya yadav
aditya yadav
1,505 Points

Pls help with code

I am unable to properly understand the question

even.py 
import random
start=5
while(start):
    num=random.randint(1,99)
    def even_odd(num):
            if num%2==0:
                print('{} is even'.format(num))
            else:
                print('{} is odd',format(num))
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
            return not num % 2
    start=start-1

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

You code seems to have gotten jumbled. The function even_odd should be kept outside and separate from the while loop. The function will be called as needed from within the while loop.

  • change the if condition to even_odd(num). This returns a True/False result
  • the second format method has a typo: replace preceding comma with a period.

Post back if you have more questions. Good Luck!!

aditya yadav
aditya yadav
1,505 Points
aditya yadav
aditya yadav
1,505 Points

Thank you, i misunderstood the question