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Start your free trialAndrey Klimushin
3,614 PointsPls help to figure out how to defined 'arg' to make my script work
Pls help to figure out how to defined 'arg' to make my script work
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
def squared(arg):
while True:
try:
arg = int()
print(arg**2)
return
except ValueError:
print(arg* len(arg))
return
squared(arg)
2 Answers
Steven Parker
231,248 PointsHere's a few hints:
- just define your function, don't call it yourself (the challenge does that for you)
- you don't need a loop (because of the return's, it can't loop anyway)
- you need to pass an argument to int that you want it to convert
- you need to return the values, not print them
I'll bet you can get it now, but if you're still stuck... <button' onclick='$("#spoiler").slideDown("slow");$(this).remove()'>Press to Reveal Spoiler</button> <div id='spoiler' style='display:none'>
SPOILER ALERT
def squared(arg):
try:
arg = int(arg)
return arg ** 2
except ValueError:
return arg * len(arg)
</div>
Andrey Klimushin
3,614 PointsThanks so much for the explanation! Now I see...