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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Felix Putra
.a{fill-rule:evenodd;}techdegree
Felix Putra
Python Web Development Techdegree Student 1,927 Points

Please help, I keep getting "Wrong number of prints" error message for this code challenge

I can't find my mistakes and don't know why I keep getting this error. I really appreciate your help and thank you guys in advance!

even.py 
import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start == True:
  num = random.randint(1, 99)
  if even_odd(num):
    print("{} is even".format(num))
  else:
    print("{} is odd".format(num))
  start -= 1

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Oh wow! You're so close it's silly! It wants the while loop to run while start is generically truthy. Remember there are lots of other values besides True that are "truthy". So if you take your code and remove the '== True' part, it passes! Take a look at the edited line you need:

while start:

Give it a whirl!

edited for further explanation

I forgot to point out that the reason it's the wrong number of prints is that start originally has a value of 5. That's a "truthy" value, but it's not explicitly equal to True. This means that when it gets down to the while loop and says while start == True it fails. Start is still explicitly equals to 5. So the loop never runs.

Felix Putra
.a{fill-rule:evenodd;}techdegree
Felix Putra
Python Web Development Techdegree Student 1,927 Points

Thanks!