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Start your free trialMaria Patiño
6,578 PointsPlease help! I don't understand why my code isn't working with the console object
I don't get it, I keep rechecking my work again and again but I don't know where my syntax error is
// I have setup a java.io.Console object for you named console
String firstName = "Maria" ;
printf = "MARIA can code in Java!" ;
3 Answers
jb30
44,806 Pointsprintf = "MARIA can code in Java!" ;
attempts to set the value "MARIA can code in Java!"
to a variable named printf
, but a variable named printf
was not previously declared.
To pass a variable arg
into a method named printf
, you would use printf(arg);
Since the printf
method is from the console object console
, this changes to console.printf(arg);
.
Maria Patiño
6,578 PointsThank you so much! jb30
T.T but my code doesn't work yet... what am I doing wrong!? T.T
This is my code:
// I have setup a java.io.Console object for you named console String firstName = "Maria"; console.printf(arg); console.printf(arg) = "MARIA can code in Java!";
jb30
44,806 Pointsarg
was meant to be an arbitrary name for a variable.
String firstName = "Maria";
console.printf(firstName);
would print Maria
.
String s = "hi";
console.printf(s);
would print hi
.
You could also pass in a string directly:
console.printf("MARIA can code in Java!");
would print MARIA can code in Java!
Maria Patiño
6,578 PointsThank you so much! You're an angel