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Linh Tran
177 PointsPlease explain the request:Use that string with a .format() on our existing menu variable and replace the current value?
I don't understand this question of code challenge: Challenge Task 3 of 3 It means i need to create a new menu, right?
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes=available.split(";")
", ".join(sundaes)
new_string="Menu includes:"+", ".join(sundaes)
menu="Our available flavors are: {}".format(",".join(sundaes))
menu=menu.format(new_string)
2 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsYou are so very close. In your join, a SPACE is needed after the comma:
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes=available.split(";")
# ", ".join(sundaes) # <-- line not needed
# new_string="Menu includes:"+", ".join(sundaes)) # <-- line not needed
menu="Our available flavors are: {}".format(", ".join(sundaes)) # <-- added space
# menu=menu.format(new_string) # <-- line not needed
Linh Tran
177 PointsThanks for helping, Chris. I get the point now.
Scott Wysocki
2,222 PointsScott Wysocki
2,222 PointsHi, Chris.
The solution your provided isn't working for me. Here is the question asked in this task in full:
Combine the sundaes list into a new string, joining them with a comma and a space (", "). Use that string with a .format() on our existing 'menu' variable and replace the current value of 'menu'.
When I attempt to change the value of 'menu' as such:
menu = menu.format(", ".join(sundaes))I am told that there wasn't the right series of sundaes and commas in "menu".
I noticed that when I use the code I just entered above, the string I'd get from ", ".join(sundaes) turns back into a list.
Any suggestions? Thanks