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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Reign Anu
Reign Anu
1,537 Points

piggy back

Aaron here it is

even.py 
import random
start=5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == True:
    num= random.randint(1,99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{] is odd".format(num))
    start-=1

1 Answer

Christian Rowden
Christian Rowden
2,278 Points
Christian Rowden
Christian Rowden
2,278 Points

It looks like one of your print statements are wrong. Also, it looks like you're referencing even_odd(num) when you should most likely only reference num instead of even_odd(num). The statement should look something like:

num= random.randint(1,99) if num % 2 == 0: print.....

Cheers and happy coding