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Java Java Basics Getting Started with Java IO

chase singhofen
chase singhofen
3,811 Points

pass the `firstName` parameter to the printf function? it also says i need to use %s i have used both but no success

pass the firstName parameter to the printf function? it also says i need to use %s i have used both but no success

IO.java
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = "chase";
console.readLine("chase");

String lastName = "singhofen";
console.readLine("singhofen");


console.printf(" %s First Name: firstName");

1 Answer

Chris Adamson
Chris Adamson
132,143 Points

The intermediate String aren't necessary, you can simply read into the variables with the readLine, and then use the firstName in the printf. The firstName is included as a parameter to the printf method, it's not part of the String:

// I have imported java.io.Console for you.  It is a variable called console.
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine();
String lastName = console.readLine();

console.printf("First name: %s", firstName);