Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

Question

I've written the code like this
for item in items:
   print(item)
if item == "STOP"
   break
else:
   print(item)
what is wrong with the code or is there any mistake or identation problem... please help!!
breaks.py
def loopy(items):
    # Code goes here
    for item in items :
        print(item)
    if item == "STOP":
        break
    else:
        print(item)

Jerehme Gayle · Accepted Answer

Hello Surendra Singh,
You are on the right path you have a couple of indentation errors (if & else) and an extra print(item).
Below is your code with the mentioned errors changed.
```python
def loopy(items):
    # Code goes here
    for item in items:
        if item == 'STOP':
            break
        else:
            print(item)
```
Happy Coding

Teddy Tinotenda Simbi · Answer

def loopy(items):
    for loopy in items:
        if items == "STOP":
            break
        else:
            print(items)

Henrik Christensen · Answer

You can make the code even shorter by removing the else-statement entirely:
```python
def loopy(items):
    # Code goes here
    for item in items:
        if item == 'STOP':
            break
        print(item)

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Aakriti Singh

Aakriti Singh

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

3 Answers

Jerehme Gayle

Jerehme Gayle

Henrik Christensen

Henrik Christensen

Teddy Tinotenda Simbi

Teddy Tinotenda Simbi