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Python Python Basics (2015) Shopping List App Break

Alexandre Gagarochkine
Alexandre Gagarochkine
426 Points
Posted by Alexandre Gagarochkine
Alexandre Gagarochkine
426 Points

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

Hi i dont know what's wrong? Thanks

breaks.py 
def loopy(items):
    for item in items:
        print(item)
    if item == "STOP":
         break
    else:
         print(item)
    # Code goes here

2 Answers

Justyna Julia Jamr贸z
Justyna Julia Jamr贸z
13,354 Points
Justyna Julia Jamr贸z
Justyna Julia Jamr贸z
13,354 Points

Your if statment is outside for loop. Try this:

def loopy(items):
    for item in items:
        print(item)
        if item == "STOP":
            break
        # Code goes here
Brian Galassini
Brian Galassini
3,521 Points
Brian Galassini
Brian Galassini
3,521 Points

Logically, you're telling the program to print everything in items and then you're telling it after the fact if the item=="STOP", then it should break. In sequence, you should add the exception to the rule "it item =="STOP: then you should tell the program what it should do if the item doesn't =="STOP". That way it will check each item to see if it =="STOP" then print if it doesn't. Think of it as a list that you have to follow the first rule before following the second.