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6,733 Pointsnumeric and aggregate functions challenge 3
Totally stumped! sorry so long
I tried SELECT AVG(score) AS average_all_scores FROM reviews;
but I get an error referencing the lack of min_score used. I don't follow this tip.
Also, the word "joint" here sounds like we are looking perhaps for a RIGHT OUTER JOIN between reviews and movies (two tables) but the question says "movie's" (my quotes) - is this a typo? Neither the Reviews nor Movies tables has a movie (singular) column.
I don't usually look for an answer outright, but this time I'm clueless. Thank you.
1 Answer
Nathan Smutz
9,492 PointsI successfully used the same answer.
I think the site just glitched in this case. The "min_score" hint sounds like it's for the previous question (2).
I'd just try it again; maybe after logging out and back in or restarting your browser.
dotz
6,733 Pointsdotz
6,733 Pointsugh! Thank you for taking the time. I will try logging out next time before posting a question too.