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Python Python Basics (2015) Logic in Python Try and Except

Posted by Sri lakshmi Kancherla
Sri lakshmi Kancherla
3,095 Points

not understanding what I am doing wrong in the code

Bummer! add did not return the correct result.

not really getting what is wrong as its working in workspace.

thanks Sri

trial.py 
def add(num1,num2):
    try:
         total = float(num1) + float(num2)
    except ValueError:
         return()
    else:
        return(total)

4 Answers

Gabbie Metheny
Gabbie Metheny
33,778 Points
Gabbie Metheny
Gabbie Metheny
33,778 Points

Everything looks great, just two slight tweaks are needed to your return statements. You don't need the () for a return, and Kenneth wants you to explictly return None in the except block, using keyword None. Then it should pass!

Sri lakshmi Kancherla
Sri lakshmi Kancherla
3,095 Points

Hey thanks much , just got it .

Thank you Sri

Sri lakshmi Kancherla
Sri lakshmi Kancherla
3,095 Points
Sri lakshmi Kancherla
Sri lakshmi Kancherla
3,095 Points

Hi all, I got it fix it , its only successful when I give return None and not return()

Thanks Sri

Keith Whatling
Keith Whatling
17,759 Points
Keith Whatling
Keith Whatling
17,759 Points

You are on the right track, two minor issues here.

Firstly, you have parenthesis on your return statements, this I think would return a tuple.

Secondly; the value error is returning a blank tuple, not None. None is a reserved word in python for being explicit about nothing.

def add(num1,num2):
    try:
         total = float(num1) + float(num2)
    except ValueError:
         return None
    else:
        return total
Manish Giri
Manish Giri
16,266 Points
Manish Giri
Manish Giri
16,266 Points

For the except block, you should return None.