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Start your free trialJesse Miller
7,920 PointsNot sure why this isn't working :(
The code is attached, but i just don't know why it doesn't work. :(
def loopy(items):
for i in items:
if i =="a":
continue
else:
print i
1 Answer
jcorum
71,830 PointsHere you go:
def loopy(items):
# Code goes here
for i in items:
if i[0] == 'a':
continue
else:
print(i)
The challenge says If the current item's index 0 is the letter "a", so you need subscript notation to get to the item in items.