Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Continue

Jesse Miller
Jesse Miller
7,920 Points

Not sure why this isn't working :(

The code is attached, but i just don't know why it doesn't work. :(

breaks.py
def loopy(items):
    for i in items:
      if i =="a":
        continue
      else:
        print i

1 Answer

Here you go:

def loopy(items):
    # Code goes here
    for i in items:
      if i[0] == 'a':
        continue
      else:
        print(i)

The challenge says If the current item's index 0 is the letter "a", so you need subscript notation to get to the item in items.