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Joeseph Wolfe
Courses Plus Student 1,010 PointsNot sure why this is not working for me, this works in my interpreter as desired
def squared(value):
if isinstance(value, int) == True:
return int(value) ** 2
else:
return value * len(value)
This code seems to work as desired for me but the quiz is returning "Bummer 'squared' didn't return the right answer.' When it has.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(value):
if isinstance(value, int) == True:
return int(value) ** 2
else:
return value * len(value)
2 Answers
Steven Parker
231,248 PointsThe challenge says that the function should return the argument squared if it can be converted into an integer.
But your function is only doing that if the argument already is an integer. You may have overlooked the distinction if you only tested it with integers and non-numeric strings.
You just need to replace your if isinstance...else with try...except.
Joeseph Wolfe
Courses Plus Student 1,010 PointsThanks Steven, I figured they wanted it done a certain way so I re-read again and used a try/except and I got a correct answer.