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Python Python Basics (2015) Letter Game App Even or Odd Loop

drstrangequark
drstrangequark
8,273 Points

Not sure what's wrong with my code

The challenge is:

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

When I try the attached code, I get an error that says Task 1 is no longer passing (Task 1 was to import random). I'm pretty sure my code is correct. Any idea whats going on here?

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    num = random.randint(1,99)
    if even_odd(num):
        print('{} is even'.format(num))
    else
        print('{} is odd'.format(num))
    start -= 1

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You've encountered the most common reason for receiving a "Task 1 is no longer passing" message. You've introduced a syntax error into your code which means that it can no longer be compiled/interpreted.

In short, you're off by one whole character. You simply forgot a colon on your else statement.

You wrote :

else
    print('{} is odd'.format(num))

But you meant to write:

else:  #note the colon here
    print('{} is odd'.format(num))

Hope this helps! :sparkles:

drstrangequark
drstrangequark
8,273 Points

Wow, I feel dumb. Thank you so much! I need to drill into my head to remember the colons!

Your else is missing a colon.