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Python Python Basics (2015) Shopping List App Continue

Posted by Joeseph Wolfe
Joeseph Wolfe
Courses Plus Student 1,010 Points

Not sure howto resolve this challenge

I tried to resolve this one by setting up the loop like this: for item in items: if item == 'a': continue print(item)

This works in my interpreter so say if I create a list called item's and I have 'a' assigned to index[0], the if statement will skip it. However this is still giving me a bummer "Didn't find any items being printed...." WEIRD

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item == 'a':
            continue
        print(item)

1 Answer

Russell Sawyer
seal-mask
.a{fill-rule:evenodd;}techdegree
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Points
Russell Sawyer
.a{fill-rule:evenodd;}techdegree
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Points

Hi Joeseph,

You are very close. The challenge is asking to iterate through the items unless the item with the index[] value of 0 is == to "a".

To check for the 0 index you need to use []. item[0]

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)